Choose the equation of a line that is parallel to y = 3x - 2 and passes through the point (-1,-6).
y = 3x + 3
y = 3x - 3
y = (-1/3)x + 19/3
y = (-1/3)x - 19/3
*i think it's the last one!
The slope must be 3. That is the "m" term in the form
y = m x + b
So the correct answer must be one of the first two. Plug in x = -1 to both of the first two equations and see which one gives you y = -6. That will be the equation that passes through the (-1, -6) point.
To check if the point (-1, -6) lies on the line represented by the equation y = 3x + 3, substitute x = -1 and solve for y:
y = 3(-1) + 3
y = -3 + 3
y = 0
Since y ≠ -6 when x = -1, the equation y = 3x + 3 is not the correct equation that passes through the point (-1, -6).
Now, let's check the other option y = 3x - 3:
y = 3(-1) - 3
y = -3 - 3
y = -6
Since y = -6 when x = -1, the equation y = 3x - 3 is the correct equation that passes through the point (-1, -6).
Therefore, the equation of the line that is parallel to y = 3x - 2 and passes through the point (-1, -6) is y = 3x - 3.