4. Translate to an equation:
p $25 potted plants and s $20 shrubs total $300
Graph the equation and use the graph to determine three different combinations of potted plants and shrubs that total $300. Submit your graph through the dropbox.
25 p + 20 s = 300
(p,s)
(0,15)
(12,0)
(4,10)
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To translate the given problem into an equation, let's represent the number of potted plants as "p" and the number of shrubs as "s".
According to the problem, the cost of each potted plant is $25, and the cost of each shrub is $20. The total cost of all the potted plants and shrubs is $300.
So, we can express this information as the equation:
25p + 20s = 300
Now, let's graph this equation to determine three different combinations of potted plants and shrubs that total $300.
To graph the equation, we need to choose values for either "p" or "s" and solve for the other variable.
Let's assume arbitrary values for "p" and solve for "s":
1. p = 0
If we have zero potted plants, then the equation becomes:
25(0) + 20s = 300
Simplifying, we get:
20s = 300
Dividing both sides by 20, we find:
s = 15
So, the first combination is 0 potted plants and 15 shrubs.
2. s = 0
If we have zero shrubs, then the equation becomes:
25p + 20(0) = 300
Simplifying, we get:
25p = 300
Dividing both sides by 25, we find:
p = 12
So, the second combination is 12 potted plants and 0 shrubs.
3. p = 6
Let's choose another value for "p" and find "s":
25(6) + 20s = 300
Simplifying, we get:
150 + 20s = 300
Subtracting 150 from both sides, we have:
20s = 150
Dividing both sides by 20, we find:
s = 7.5
So, the third combination is 6 potted plants and 7.5 shrubs.
Now, you can plot these combinations on a graph to visualize them.