The length of a rectangular lot is 50 feet more than the width. If the perimeter is 500 feet, then what are the length and width?
how about 2w + 2(w+50) = 500 ??
The Perimeter of a rectangular porch is 72 feet. The porch's length is 5 times its the width. You want to determine the dimensions of the porch?
To find the length and width of the rectangular lot, we can set up a system of equations based on the given information.
Let's say the width of the lot is "w" feet. According to the problem, the length is 50 feet more than the width, so the length can be represented as "w + 50" feet.
The formula for the perimeter of a rectangle is P = 2L + 2W, where P is the perimeter, L is the length, and W is the width.
Given that the perimeter is 500 feet, we can write the equation as:
500 = 2(w + 50) + 2w
Now, let's solve this equation to find the value of "w" (width):
500 = 2w + 100 + 2w
500 = 4w + 100
400 = 4w
w = 400/4
w = 100
So, the width of the lot is 100 feet.
Now, we can find the length:
Length = Width + 50
Length = 100 + 50
Length = 150
Therefore, the length of the lot is 150 feet and the width is 100 feet.