in a bike race, ramit and keith started at the same time abd rode with constant speeds. Ramit rode 30 miles per hour, and keith rode at 35 miles per hour. If ramit crossed the finish line 10 minutes after keith, how many miles long was the race?
10 min = 1/6 hr
distance = rate * time
30 t = 35 (t-1/6)
30 t = 35 t - 35/6
35/6 = 5 t
t = 7/6 hr
d = 30 t = 30*7/6 = 5*7 = 35 miles
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juan entered a bike race which he was to ride 45 miles. stopping at certain intervals during the race to check in with the scorers .he checked in 9 times before crossing the finish line if the intervals wre eaqually spaced throughoutthe race,how far apart were they?
To solve this problem, we can use the formula: Distance = Speed x Time.
Let's denote the length of the race as "d" (in miles).
Given that Ramit rode at a speed of 30 miles per hour and crossed the finish line after Keith, we can say:
Distance covered by Ramit = Distance covered by Keith + 10 minutes (or 10/60 hours).
Using the formula, we can write the equation:
30 * (d) = 35 * (d) + 10/60
To solve for "d," we can simplify the equation:
30d = 35d + 1/6
Subtracting 35d from both sides:
-5d = 1/6
Now, isolate "d" by dividing both sides by -5:
d = (1/6) / -5
This simplifies to:
d = -1/30
Since you cannot have a negative distance, it seems there might be an error in the given information or question, as the distance should be positive. Please double-check the question or provide additional information if necessary.