# Physics

A constant net force of 406 N, up, is applied to a stone that weighs 33 N. The upward force is applied through a distance of 2.4 m, and the stone is then released. To what height, from the point of release, will the stone rise?

Thoughts: !@#\$%^&ma. Would the acceleration be g? You would divide the weight by g to get the mass of the stone, correct?

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1. The acceleration a is given by
a = F/m = 12.30 m/s^2
The velocity when released is
V = sqrt (2aX) = 7.68 m/s
The height H that it reaches after that is given by
gH = V^2/2
H = V^2/(2g)

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posted by drwls

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