Calculus

Need help with this complex number equation.



8-3i/-4-6i=

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asked by Josh
  1. I am sure you meant
    (8-3i)/(-4 - 6i)

    multiply top and bottom by (-4+ 6i)
    (8-3i)/(-4 - 6i)* (-4+ 6i)/ (-4+ 6i)
    = (-32 + 48i + 12i - 18i^2)/(16 - 36i^2)
    = (-32 + 60i + 18)/(16+36)
    = (-14 + 60i)/52
    = (-7 + 30i)/26 or -7/26 + 30i/26

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    posted by Reiny

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