precal 2

find values for b such that the triangle has no solution A=88 degree, a=315.6

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  1. assume angle B = 90°, then b has one solution, namely
    sin88 = 315.6/b
    b = 315.6/sin88 = 316.79

    so there is no solution for b > 316.79

    check: let b = 320
    find angle B
    sin88/315.6 = sinB/320
    sinB = 320sin88/315.6 = 1.0133.. which is not possible.

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    posted by Reiny

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