algebra

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15t^2+7t=2

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asked by sheba
  1. 15t^2 + 7t -2 = 0

    (5t-1)(3t+2) = 0

    t = -2/3, 1/5

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    posted by PsyDAG
  2. t =(-b�}�ã(b^2-4ac))/2a

    t =(-7�}�ã(7^2-4(15)(-2)))/(2(15))

    t=(-7�}�ã(49 +120))/30

    t=(-7�}�ã169)/30

    t=(-7�}13)/30

    t=(-7+13)/30 = 6/30 = 1/5

    t=(-7-13)/30 = -(20/30) = -(2/3)

    Therefore, t = 1/5 & -(2/3)

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    posted by Mithra

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