math

A rectangular poster has an area of 190in(squared). The height of the poster is 1in. less than twice its width. Find the dimensions of the poster.

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  1. A = Area= 190 in^2

    H = Hight

    W = Width


    H = 2W-1


    A = W*H

    A = W*(2W-1)

    190 = 2W*W-1*W

    190 = 2W^2-W

    2W^2-W-190 = 0

    The exact solutions of this equation are:

    W=10

    and

    W= -19/2

    Width can't be negative so:

    W = 10 in

    H = 2*W-1

    H = 2*10-1

    H = 20-1

    H = 19 in


    W = 10 in


    H = 19 in


    A = W*H

    A = 10*19

    A = 190 in^2


    If you don't know solve quadratic equation, in google type:

    quadratic equation online

    When you see list of results click on:

    Free Online Quadratic Equation Solver:Solve By Quadratic Formula

    When page be open in rectangle type:

    2W^2-W-190=0

    and click option: solve it!

    You will see solution step-by-step

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