A 50g sample of metal was heated to 100 degrees Celsius and then dropped into a beaker containing 50g of water at 25 degrees Celsius. If the specific heat of the metal is .25 cal/g degrees Celsius, what is the final temperature of the water?
(units are degrees Celsius)
I don't know how to go about solving this. Help please?
heat lost by metal + heat gained by water = 0
[mass metal x specific heat metal x (Tfinal-Tinitial)] + [mass H2O x specific heat water x (Tfinal-Tinitial)] = 0
Substitute and solve for Tfinal, the only unknown.posted by DrBob222
Sample of gas is heated from 25c to 55c it will expand byposted by starese
wecrwtveyposted by vrydfvg