find the maximum value of h2(g)in grams that would be expected to form by reacting 6.54g of zinc with 50ml of 0.1M of HCl.
To find the maximum value of h2(g) in grams that would be expected to form, we need to follow a few steps:
Step 1: Write the balanced chemical equation for the reaction between zinc (Zn) and hydrochloric acid (HCl).
Zn + 2HCl -> ZnCl2 + H2
Step 2: Calculate the number of moles of zinc (Zn) using its given mass.
We have the mass of zinc (Zn) as 6.54 grams. To convert grams to moles, we need to know the molar mass of zinc. The molar mass of Zn is 65.38 g/mol (you can find this information on the periodic table).
Moles of Zn = Mass of Zn / Molar mass of Zn
Moles of Zn = 6.54 g / 65.38 g/mol
Moles of Zn = 0.1 mol
Step 3: Determine the limiting reactant.
To determine the limiting reactant, we compare the mole ratio of Zn to H2 from the balanced equation. In the balanced equation, the ratio of Zn to H2 is 1:1. This means that 1 mole of Zn reacts with 1 mole of H2.
Since we have 0.1 mole of Zn, we can conclude that 0.1 moles of H2 will be produced as well.
Step 4: Calculate the mass of H2(g) produced from the limiting reactant.
To calculate the mass of H2(g) produced, we need to know the molar mass of hydrogen gas (H2). The molar mass of H2 is 2.02 g/mol (you can find this information on the periodic table).
Mass of H2 = Moles of H2 x Molar mass of H2
Mass of H2 = 0.1 mol x 2.02 g/mol
Mass of H2 = 0.202 g
Therefore, the maximum value of h2(g) that would be expected to form is 0.202 grams.