Na2CO3 + 2HCl = CO2 + H2O + 2NaCl. What mass of CO2 is produced from the reation of 2.94g Na2CO3 with excess HCI?g
Here is a worked example of a stoichiometry problem. http://www.jiskha.com/science/chemistry/stoichiometry.html
To calculate the mass of CO2 produced from the reaction, we need to determine the limiting reagent first. The limiting reagent is the reactant that gets completely consumed, thus limiting the amount of product formed. In this case, it's given that there is an excess of HCl, so Na2CO3 will be the limiting reagent.
To find the mass of CO2 produced, we can use the stoichiometric ratio between Na2CO3 and CO2 from the balanced equation.
1 mole of Na2CO3 produces 1 mole of CO2.
The molar mass of Na2CO3 is:
2(Na) + 1(C) + 3(O) = 2(22.99 g/mol) + 12.01 g/mol + 3(16.00 g/mol) = 105.99 g/mol
Using the molar mass of Na2CO3, we can calculate the number of moles of Na2CO3 present in 2.94 g of Na2CO3:
Number of moles = mass / molar mass
Number of moles of Na2CO3 = 2.94 g / 105.99 g/mol
Now, since the stoichiometric ratio between Na2CO3 and CO2 is 1:1, the number of moles of CO2 produced will be the same as the number of moles of Na2CO3. Thus, the mass of CO2 produced can be calculated as follows:
Mass of CO2 = number of moles of CO2 x molar mass of CO2
First, let's calculate the number of moles of Na2CO3:
Number of moles of Na2CO3 = 2.94 g / 105.99 g/mol
Now, calculate the mass of CO2 produced:
Mass of CO2 = number of moles of CO2 x molar mass of CO2
Mass of CO2 = (2.94 g / 105.99 g/mol) x (44.01 g/mol)
Calculating this, we find:
Mass of CO2 = 0.082 g
Therefore, the mass of CO2 produced from the reaction of 2.94 g Na2CO3 with excess HCl is 0.082 g.
To find the mass of CO2 produced from the reaction, we need to use stoichiometry. The balanced equation tells us that the mole ratio between Na2CO3 and CO2 is 1:1.
First, calculate the number of moles of Na2CO3:
moles of Na2CO3 = mass of Na2CO3 / molar mass of Na2CO3
The molar mass of Na2CO3 (sodium carbonate) can be calculated by adding up the atomic masses of the elements:
molar mass of Na2CO3 = (2 * atomic mass of Na) + atomic mass of C + (3 * atomic mass of O)
Next, use the mole ratio to determine the number of moles of CO2 produced, which will be the same as the moles of Na2CO3:
moles of CO2 = moles of Na2CO3
Finally, calculate the mass of CO2 by multiplying the number of moles of CO2 by its molar mass:
mass of CO2 = moles of CO2 * molar mass of CO2
Let's calculate the values step by step:
Step 1: Calculate the molar mass of Na2CO3
molar mass of Na = 22.99 g/mol
molar mass of C = 12.01 g/mol
molar mass of O = 16.00 g/mol
molar mass of Na2CO3 = (2 * 22.99) + 12.01 + (3 * 16.00)
Step 2: Calculate the moles of Na2CO3
moles of Na2CO3 = 2.94 g Na2CO3 / molar mass of Na2CO3
Step 3: Calculate the moles of CO2
moles of CO2 = moles of Na2CO3
Step 4: Calculate the mass of CO2
mass of CO2 = moles of CO2 * molar mass of CO2
Note: Since HCI is present in excess, we don't need to consider its contribution to the calculation.
By following these steps, you can calculate the mass of CO2 produced from the given reaction.