algebra

Find the vertex angle of an isosceles triangle with base angles of (3x+10) and (8x-15). Show your work for credit.

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  1. So the two base angles must be equal
    8x - 15 = 3x + 10
    5x = 25
    x = 5
    so each of the base angles is 25°
    That would leave 130° for your vertex angle

    (25+25+130=180)

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    posted by Reiny

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