CALCULUS

Consider the function f(x)=sqrt(2–5x^2), –5≤x≤1. The absolute minimum value is ____ and this occurs at x equals ______?

Found the max value to be 2 at x=0.

  1. 👍 0
  2. 👎 0
  3. 👁 51
  1. f'(x) = (1/2)(2 - 5x^2)^(-1/2) )(-10x)
    = -5x(2-5x^2)^(-1/2)
    = 0 for a max/min

    This has only one solution, when x = 0

    so the min occurs when x = 0 and
    f(0) = √(2-0) = √2

    1. 👍 0
    2. 👎 0
    posted by Reiny
  2. 4x2+24x+16y2-32y-12=0 need to know how to write in the standard form for ellipse it is a precalculus

    1. 👍 0
    2. 👎 0
    posted by jamie

Respond to this Question

First Name

Your Response

Similar Questions

  1. Calculus

    f(x)=x*sqrt(x^2+2x+10) + 1*sqrt(x^2+2x+10 defined at the interval [-7,5]. A. f(x) is concave down on the region _,_. B. f(x) is concave up on the region _,_. C. The inflection point for this function is at ____? D. The minimum for

    asked by Z32 on June 18, 2009
  2. Calculus

    Let f(t)=t\sqrt{4-t} on the interval [-1,3]. Find the absolute maximum and absolute minimum of f(t) on this interval. The absolute max occurs at t=. The absolute min occurs at t=

    asked by Alessandra Romano on October 31, 2014
  3. Calculus (pleas help!!!)

    Find the absolute maximum and absolute minimum values of the function f(x)=(x−2)(x−5)^3+11 on each of the indicated intervals. Enter -1000 for any absolute extrema that does not exist. (A) Interval = [1,4] Absolute maximum =

    asked by Cady on April 5, 2011
  4. Calculus (pleas help!!!)

    Find the absolute maximum and absolute minimum values of the function f(x)=(x−2)(x−5)^3+11 on each of the indicated intervals. Enter -1000 for any absolute extrema that does not exist. (A) Interval = [1,4] Absolute maximum =

    asked by Cady on April 5, 2011
  5. calculus

    2) Let g(s)= t(4−t)^1/2 on the interval [0,2]. Find the absolute maximum and absolute minimum of g(t) on this interval. Enter DNE if the absolute maximum or minimum does not exist. The absolute max occurs at t= . The absolute

    asked by spud on October 17, 2014
  6. Math: Calculus

    Answer the following questions for the function f(x)=sin(x/4)^2 defined on the interval [-12.266371, 2.241593]. Rememer that you can enter pi for as part of your answer. a.)f(x) is concave down on the interval ____. b.) A global

    asked by NEED HELP!!!! on November 3, 2010
  7. Calculus

    Determine where the absolute extrema of f(x)=-3(x^2)+7x on the interval [1,3] occur. 1. The absolute maximum occurs at = 2. The absolute minimum occurs at =

    asked by Salman on November 7, 2009
  8. Calculus

    Find the absolute maximum and absolute minimum values of the function f(x)=x^3+6x^2-63x+4 on each of the indicated variables. Enter DNE for does not exist. (A) Interval = [-8,0] Absolute maximum = Absolute minimum = (B) Interval =

    asked by Nate on October 29, 2013
  9. CALCULUS

    Consider the function f(x)=5–4x^2 , -3≤x≤1 The absolute maximum value is __________ and this occurs at x equals ___________ The absolute minimum value is _________ and this occurs at x equals ___________

    asked by Sarah on May 19, 2012
  10. calculus

    Let g(s)=1/(s-2) on the interval [0,1]. Find the absolute maximum and absolute minimum of g(s) on this interval. The absolute max occurs at s=. The absolute min occurs at s=

    asked by Alessandra Romano on October 31, 2014

More Similar Questions