the molarity of a solution containing 40 grams of NaOH in 100 ml of solution is
To calculate the molarity of a solution, you need to use the formula:
Molarity (M) = moles of solute / volume of solution (in liters)
Step 1: Convert the mass of sodium hydroxide (NaOH) to moles.
To do this, you need to know the molar mass of NaOH, which is the sum of the atomic masses of sodium (Na), oxygen (O), and hydrogen (H).
The molar mass of NaOH = (23 g/mol) + (16 g/mol) + (1 g/mol) = 40 g/mol
Since you have 40 grams of NaOH, divide 40 g by the molar mass of NaOH to get the number of moles:
moles of NaOH = 40 g / 40 g/mol = 1 mole
Step 2: Convert the volume of the solution to liters.
You are given that the volume of the solution is 100 mL. To convert mL to liters, divide by 1000:
volume of the solution = 100 mL / 1000 mL/L = 0.1 L
Step 3: Calculate the molarity.
Now that you have the moles of NaOH and the volume of the solution in liters, substitute these values into the formula for molarity:
Molarity (M) = 1 mole / 0.1 L = 10 M
Therefore, the molarity of the solution containing 40 grams of NaOH in 100 ml of solution is 10 M.