algebra 21

Solve the equation. If necessary, round to thousandths.
3^(2x + 1) = 27

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asked by renee
  1. my bad supposed to say algebra 2

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    posted by renee
  2. 3^(2x+1) = 3^3
    2x+1 = 3
    2x=2
    x=1

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    posted by Reiny
  3. Substitute (2x + 1) for y.

    3^y = 27
    y = 3

    Back-substitute.

    2x + 1 = 3
    x = 1

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    posted by Max

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