# algebra 21

Solve the equation. If necessary, round to thousandths.
3^(2x + 1) = 27

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asked by renee
1. my bad supposed to say algebra 2

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posted by renee
2. 3^(2x+1) = 3^3
2x+1 = 3
2x=2
x=1

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posted by Reiny
3. Substitute (2x + 1) for y.

3^y = 27
y = 3

Back-substitute.

2x + 1 = 3
x = 1

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posted by Max

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