I need help solving this problem.
logbase5(x+2)=2
Hint: what is the inverse of the logarithm?
b^logb(z) = z
5^log5 (x+2) = x+2
x+2 = 5^2 = 25
x = 23
Thank you so much!
To solve the equation log base 5 of (x+2) equals 2, you need to get rid of the logarithm. Here's how you can solve it step by step:
Step 1: Write the equation in exponential form using the definition of logarithms. In this case, since the base is 5, the exponential form is: 5^2 = x+2.
Step 2: Simplify the exponential equation. 5^2 is equal to 25. So the equation becomes: 25 = x+2.
Step 3: Solve for x. To isolate x, subtract 2 from both sides of the equation: 25 - 2 = x+2 - 2, which simplifies to: 23 = x.
Therefore, the solution to the equation log base 5 of (x+2) equals 2 is x = 23.