# calculus

Let f(x)= 4x(x+3)^2 - (x+3)^3 and find the values of x that correspond to f(x)=0.

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1. Factor it first

(x+3)(x+3) [4x -(x+3)] = 0

(x+3)(x+3)[3x-3] = 0
x = -3
x = -3
x = +1

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posted by Damon
2. Thank you!

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posted by Gary

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