System of Linear Equations

A manufacturer produces three types of radios: deluxe, standard and economy. Each radio uses three different types of transistors: P, Q and R. The deluxe radio uses 2 P's, 7 Q's and 1 R. The standard contains 2 P's, 3 Q's and 1 R, and the economy model requires 1 P, 2 Q's and 2 R's.

How many radios of each type can be constructed if the total number of transistors (P's, Q's and R's) available are 2200, 3400 and 1400 respectively and all transistors must be used?

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asked by neeha
  1. number of deluxe : x
    number of standard : y
    number of econony : z

    your system is
    2x + 2y + z = 2200
    7x + 3y + 2z = 3400
    x + y + 2z = 1400

    2nd - 3rd : 6x + 2y = 2000 or ---> 3x + y = 1000

    double the 1st, subtract the 3rd
    3x+3y=3000

    subtract the x,y equations:

    2y = 2000
    y = 1000
    sub into 3x+y=1000
    3x + 1000= 1000
    3x=0
    x=0 , !!!!!????

    Unless I made some arithmetic error, I think your data is flawed.

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    posted by Reiny
  2. I get the same results, x is indeed zero.

    See:
    http://www.jiskha.com/display.cgi?id=1310358660

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