# physics

A 5.0 m diameter merry-go-round is initially turning with a 4.6 s period. What is the speed of a child on the rim?

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1. T = (2pir)/v with T being the period, r being the radius, and v being the speed. Don't forget that radius is half the diameter.

So, v*4.6s = 2*pi*2.5m

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posted by Lauren

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