Mat 117

(x+5)(x-2)(x+1)>0
What is the solution set? Why am I not getting this at all?

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asked by G
  1. easy way to do these ....

    Since the expression is already factored, you are off to a good start.
    the critical values are x = -5,-2 and 2
    (those would have been the solution had it been an equation)

    so we consider 4 sections:

    1. x < -5
    take any value in that domain, say x = -10
    we get (-)(-)(-) < 0 ----- false

    2. -5 < x < -1
    take any value in that domain, say x = -4
    (+)(-)(-) > 0 ----- true

    3. -1 < x < 2
    take any value of x in that domain, say x = 0
    (+)(-)(+) < 0 ---- false

    4. x > 2
    let's pick x = 10
    (+)(+)(+) > 0 ------ true

    so solution:
    -5 ≤ x ≤ -1 OR x > 2

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    posted by Reiny
  2. third line contains a typo, should have said ...

    the critical values are x = -5,-1 and 2

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    posted by Reiny

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