algebra system of equation

10x-5y=20
7x-5y=-26

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asked by eric
  1. Eq1: 10x-5y = 20.
    Eq2: 7x-5y = -26.
    Multiply Eq1 by -1:
    -10x+5y = -20,
    +7x-5y = -26.
    Sum:x = -3x+0 = -46,
    x = -46/-3 = 15 1/3.
    In Eq2, substitute 46/3 for x:
    7(46/3) - 5y = -26,
    Solve for y and get:
    26 2/3 = 80/3.

    Solution Set = (x,y) = (15 1/3,26 2/3).

    Check the given Eqs and make sure the signs are correct.

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    posted by Henry

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