Cal

USE INTEGRATION BY PARTS TO FIND EACH INTEGRAL
ƪxe^2x dx

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1. Please see your next post as there is the same problem.

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Sra

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2. let u = x
du/dx = 1
du = dx

let dv = e^(2x)dx
dv/dx = e^(2x)
v = (1/2)e^(2x)

formula:
[int] u dv = uv - [int] v du
[int] x e^(2x) dx = (x)(1/2)e^(2x) - [int] (1/2)e^(2x) dx
= (1/2)xe^(2x) - (1/4)e^(2x)

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posted by Reiny

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