Math-word problem

A new train goes 20% further in 20% less time than an old train. By what % is the average speed of the new train GREATER THAN that of the old train?

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  1. Let Do = 1 mi = Distance of old train.
    Dn = 1.2*Do = 1.2 * 1 = 1.2 mi = Dist.
    of new train.

    Let To = 1min = Time of old train.
    Tn = 0.8*To = 0.8 * 1 = 0.8 min. = Time
    of new train

    Vo=Do/To = 1mi/1min=1mi/min Velocity of old train.
    Vn = Dn/Tn = 1.2mi/0.8min = 1.5 mi/min = Velocity of new train.

    Vn/Vo = 1.5/1 = 1.5 = 150%,
    % Greater = 150% - 100% = 50%.

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    posted by Henry
  2. the answer before mine is wrong becaude it is actually 65%

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    2. 👎 0
    posted by anika
  3. It's 50%.

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    posted by Lol

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