Find the perimeter and area of a right triangle if the shortest side is 20 mm. and the longest side is 52 mm.

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1. The longest side of a right triangle is the hypotenuse, c in
a^2 + b^2 = c^2
so
a^2 + 20^2 = 52^2
a^2 = 2704 - 400 = 2304
a = 48

perimeter = 48 + 20 + 52 = 120 mm
area = (1/2)48(20) = 480 mm^2

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posted by Damon
2. oh thank you so much!! i was totally off...

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posted by Jen
3. You are welcome :)

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posted by Damon

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