solve using quadratic formula
p²+5p-5=0
p = [ -5 +/- sqrt(25+20) ]/2
p = -2.5 +/- .5 sqrt(45)
p - -2.5 +/- 1.5 sqrt(5)
p=1.381
p=3.628
is what I came up with...
I don't think so but put your values back in and see if they work.
To solve the quadratic equation p² + 5p - 5 = 0 using the quadratic formula, you need to follow a few steps:
Step 1: Identify the coefficients of the quadratic equation.
The quadratic equation is in the form ax² + bx + c = 0, where a, b, and c are the coefficients. In this case:
a = 1 (coefficient of p² term)
b = 5 (coefficient of p term)
c = -5 (constant term)
Step 2: Write the quadratic formula.
The quadratic formula is p = (-b ± √(b² - 4ac)) / (2a).
Step 3: Substitute the coefficients into the quadratic formula.
Substituting the coefficients from the given equation, you get:
p = (-(5) ± √((5)² - 4(1)(-5))) / (2(1)).
Step 4: Simplify the expression.
Now, simplify the expression inside the square root:
p = (-5 ± √(25 + 20)) / 2.
p = (-5 ± √45) / 2.
p = (-5 ± 3√5) / 2.
So the solutions to the quadratic equation p² + 5p - 5 = 0 are p = (-5 + 3√5) / 2 and p = (-5 - 3√5) / 2.