Algebra II

A projectile is thrown upward so that its distance above the ground after t sec is given by h(t)=-11t²+264t. After how many seconds does it reach its maximum height?

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asked by HELP
  1. 11 t^2 - 264 t = - h

    t^2 - (264/11 )t = -(1/11) h

    t^2 - (24)t + 144 = -h/11 + 144

    (t-12)^2 = -h/11 + 144

    t = 12 at vertex

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    posted by Damon
  2. A projectile is thrown upward so that its distance​ (in feet) above the ground after t seconds is given by
    h left parenthesis t right parenthesis equals negative 15 t squared plus 420 t.
    h(t)=−15t2+420t. What is its maximum​ height?

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