Starting from rest, a car accelerates at 2.5 m/s^2 up a hill that is inclined 5.4 ^\circ above the horizontal.
how far the car travel horizontally in 15s?

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  1. I'm assuming the angle of inclination is 5.4 deg.

    a(h) = 2.5m/s^2 * cos5.4 = 2.49m/s^2 =
    hor. component of acceleration.

    d = Vo*t + 0.5at^2,
    d = 0 + 0.5*2.49*(15)^2 = 280m.

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