Chem balancing equation

C5H602+O2 ---> CO2+H2O

what is the coefficient of O2?

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  1. C5H602 + O2 ---> CO2+H2O

    start with C
    C5H602 + ? O2 ---> 5 CO2+ ? H2O

    now H
    C5H602 + ? O2 ---> 5 CO2+ 3 H2O

    10 + 3 = 13 O on right

    so
    need 11 O from O2
    so
    C5H602 + 5.5 O2 ---> 5 CO2+ 3 H2O
    so double everything to get rid of fraction
    2C5H602 + 11 O2 ---> 10 CO2+ 6 H2O
    so
    11

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