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Can someone help me with this question?

A water balloon is dropped from the top of a building. Assume the balloon does not break when it strikes the ground. If the water balloon falls a distance of 21m, what is the maximum temperature rise of the water balloon due to it being dropped?

I'm not sure where to begin!

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  1. The potential energy becomes heat, Q.
    Use the heat to compute the temperature rise.

    Delta T = Q/(M*C) = (1/2)M g H/(M*C)
    = (1/2)g H/C
    C is the water specific heat, 4180 joules/kg C

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