Solve the indicated set 6 - 3x = - 31; (reals)
from zero go right 3,
then from there go right 5 more
and end up at 8
from zero go left 6,
then from there go right 3
and end up at -3
what? On another site I got told to subtract six from both sides leaving -3x = -37, then divid by -3 and get x = 37/3...sooo
To solve the equation 6 - 3x = -31 for x, we need to isolate the variable on one side of the equation. Here's how to do it step-by-step:
Step 1: Start with the equation 6 - 3x = -31.
Step 2: To eliminate the constant term on the left side of the equation, subtract 6 from both sides:
6 - 6 - 3x = -31 - 6
-3x = -37
Step 3: Now, we need to isolate the variable x. To do this, divide both sides of the equation by -3:
(-3x) / -3 = (-37) / -3
x = 37 / 3
Thus, the solution to the equation 6 - 3x = -31 (considering the set of real numbers) is x = 37 / 3.