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Calculus
The line that is normal to the curve x^2=2xy3y^2=0 at(1,1) intersects the curve at what other point? Please help. Thanks in advance. We have x2=2xy  3y2 = 0 Are there supposed to be 2 equal signs in this expression or is it x2 +
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identify the conic sections below (circle,hyperbola,parabola,ellipse). a)3x2+3y22y=4 b)3x29y2+2x4y=7 c)2x2+5y27x+3y4=0 d)3y24x+17y=10
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The parabolas y = 3x2 + 10x  6 and y = 3x2  17x + 2 intersect at _____? A.the line y = 27x  8. B. x=the square root of 2 over 3 and xthe square root of 2 over 3. C. x=8/27. D. they do not intersect.
asked by Tifini on July 8, 2012 
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Find all points on the curve x^2y^2+xy=2 where the slope of tangent line is 1. This is what I got. x^2y^2+xy=2 x^2*2ydy/dx + 2x*y^2 + x*dy/dx + y =0 dy/dx(2yx^2+x)= 2xy^2y dy/dx = (2xy^2y)/(x+2yx^2) how do I finish from here?
asked by Riley on April 2, 2009
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