# physics

A particle at rest undergoes an acceleration of 2.5 m/s^2 to the right and 3.2 m/s^2 up. What is its speed after 5.9s? Answer in m/s

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1. The magnitude of the acceleration is
a = sqrt[2.5^2 + 3.2^2] = 4.06 m/s^2,
since the two directions are perpendicular.

The speed after 5.9s is 5.9 a

You do the multiplication.

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