Physics

1. If a 500N person is skiing on a slope with an angle of incline of 67 degrees and there was a friction coefficient of 0.19, determine the person’s acceleration rate. If starting from rest, what is the overall displacement after 30 seconds?

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  1. acceleration rate a = Fnet/M

    M = 500/g = 51.0 kg

    Fnet = (weight component down slope) - (friction)
    = W sin67 - W cos67*0.19
    = 460 - 37 = 423 N

    Now you can calculate a.

    The displacement in time t is (1/2)at^2.

    It is highly unlikely this high acceleration rate (a) could be maintained for 30 seconds. Aerodynamic friction will become important after about 5 seconds.

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