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Given the quadratic function f(x) = x2 – 12x + 36, find a value of x such that f(x) = 25.

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  1. Given f(x) = x2 – 12x + 36
    and f(x)=25, equate:
    25 = x² - 12x + 36
    x&sup2-12x+11=0
    (x-11)(x-1)=0
    therefore x=11 or x=1

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