3 consecutive numbers multiply to 4080. What are the numbers?

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  1. Let the middle number be x.
    (x-1)x(x+1) = x^3 - x = 4080

    x = 16 works
    I did not solve the cubic equation, but knew the answer had to be an integer slightly larger than the cube root of 4080.

    The numbers are 15, 16 and 17.

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