calculus

find equation of a tangent line to y=x^3-5x+6 at the point where x=2

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  1. Now this is the last one. These are basis and you should try them.

    dy/dx = slope = m = 3x^2 -5
    at x = 2, m = 12-5 = 7
    so line is of form
    y = 7x+b
    at x = 2, y = 8-10+6 = 4
    so tangent at point (2,4)
    4 = 14+b
    so
    b = -10
    so
    y = 7 x -10

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