calculus

Find the dimensions of the rectangular garden of greatest area that can be fenced off for $6000, if the cost of fencing is $5 per meter.

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  1. cost = 5 (2x+2y)
    6000 = 10x + 10 y
    x+y = 600
    so y = 600-x
    A =xy = 600x-x^2

    dA/dx = 0 at max = 600 -2x
    x = 300
    then y = 300
    so square

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