How strong an electric field is needed to accelerate electrons in a TV tube from rest to one-tenth the speed of light in a distance of 4.9 cm ?

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  1. Require that

    Work done by E-field = Kinetic Energy gain

    e*E*X = (1/2) m V^2 = (1/200) m c^2

    E = (1/200)(m/e)c^2/X
    where X = 0.049 m
    m = 9.11*10^-31 kg
    e = 1.602*10^-19 C
    c = 3.00*10^8 m/s

    E = 52200 V/m

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  2. The electrons move with a velocity of 3.0x10^6 m/s. What electric field strength is needed to accelerate electrons from rest to this velocity in a distance of 9.0 mm?

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