MATH

What is the 9th term -1/18 1/6 -1/2

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asked by M
  1. (-1/18)*(r)=(1/6)
    find r.

    geometric progression:
    ar^(n-1)
    a=1st term
    r=ratio
    n=nth term

    http://www.mathsrevision.net/alevel/pages.php?page=33

    posted by TutorCat

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