College Pre-Algegra

1. Find the exact value of tan660 using the functions of 330deg.

2. Solve the equation 2sin^20+5sin0+3=0 on the interval 0<=0<2pi.

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  1. tan 660°
    = tan 300° , (660 - 360 - 300)
    = - tan 60
    = -√3/1 = -√3

    2sin^2Ø + 5sinØ + 3 = 0
    (2sinØ - 1)(sinØ + 3) = 0
    sinØ = 1/2 or sinØ = -3, the latter is not possible

    if sinØ = 1/2
    then Ø = 30° or Ø = 150°
    or
    Ø = π/6 or Ø = 5π/6

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  2. 1 7/2 divided by 7 11/12 =

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