the pH of 10.00 mL of 0.100 M HCl after adding 10.00 mL of indicator solution

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  1. The 0.100 M HCl has been diluted from 10 mL to 20 mL; therefore,
    (HCl) = 0.100 x (10/20) = 0.05M
    pH = -log(H^+)
    pH = -log(0.0500)
    pH = -(-1.301) = 1.301

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