Solve the equation log (little 3) X + log (little6

log (little 3) X + log (little6) X = 2
the answer is 3.9

can anyone please explain how do you get this answer? Thank you

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  1. log3 x + log6x = 2

    we can change bases by
    logloga b = log b/log a , (base 10)

    so your equation is
    logx/log3 + logx/log6 = 2
    logx(1/log3 + 1/log6) = 2
    logx = 2/(1/log3 + 1/log6) = .59154 appr.
    x = 10^.59154 = 3.904

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