chemistry

determine half life of krypton-92 if only 6.0 millograms of an original 96.0 sample remains unchanged after 7.36 seconds

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  1. ln(No/N) = kt
    No = 96
    N = 6
    k = unknown
    t = 7.36 seconds.
    Then substitute k into the below equation.
    k = 0.693/t1/2 and solve for t1/2.

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  2. 1.84 seconds

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