Question

0.255 g sample of H2C2O4 required 25.70 mL of NaOH to neutralize, what would you report as the molarity of NaOH solution? the reaction is as follows:

H2C2O4(aq) +2 NaOH (aq) -> Na2C2O4(aq) +2 HOH (l)

Answer 1

moles H2C2O4 = grams/molar mass = ??

Using the coefficients in the balanced equation, convert moles H2C2O4 to moles NaOH. That will be ??moles H2C2O4 x (2 moles NaOH/1 mole H2C2O4) = ??moles H2C2O4 x 2 = xx moles NaOH.
Then M NaOH = moles NaOH/L NaOH, and round to the appropriate number of significant figures.

Answer 2

.220 mol per liter

Answer 3

I agree.

Answer 4

Thank you!

Answer 5

[AI-generated answer — Explain Bot]

To determine the molarity of the NaOH solution, we can use the equation

moles of H2C2O4 = moles of NaOH.

First, let's find the number of moles of H2C2O4 using its molar mass.

The molar mass of H2C2O4 is:
2(1.008 g/mol) + 2(12.01 g/mol) + 4(16.00 g/mol) = 90.034 g/mol.

Given that we have 0.255 g of H2C2O4, we can convert it to moles:

moles of H2C2O4 = (0.255 g) / (90.034 g/mol) ≈ 0.00283 mol.

According to the balanced equation, the ratio between H2C2O4 and NaOH is 1:2. Therefore, the number of moles of NaOH is double that of H2C2O4:

moles of NaOH = 2 * (0.00283 mol) = 0.00566 mol.

Now, we can use the volume of NaOH used to determine the molarity of the solution.

Molarity (M) is defined as moles of solute divided by the volume of solvent in liters (L).

Molarity of NaOH = moles of NaOH / volume of NaOH in liters.

The volume of NaOH used is given as 25.70 mL. To convert it to liters, divide by 1000:

volume of NaOH in liters = 25.70 mL / 1000 = 0.0257 L.

Now, calculate the molarity of NaOH:

Molarity of NaOH = 0.00566 mol / 0.0257 L ≈ 0.22 M.

Therefore, the molarity of the NaOH solution is approximately 0.22 M.