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A bag contains 10 red and 8 green marbles. 5 marbles are selected without replacement. What is the probability that exactly 2 are green?

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  1. One possible outcome is
    GGRRR
    the prob of that is (8/18)(7/17)(10/16)(9/15)(8/14)
    = 2/51

    But the 2 G's and the 3 R's can be arranged in
    5!/(2!3!) or 10 ways

    so prob of your event = 10(2/51) = 20/51

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