algebra 2

if a3 = 20 and a6=41 for an arithmetic sequence, find a1

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  1. a(6)=a(1)+(6-1)d
    a(3)=a(1)+(3-1)d
    Subtract:
    a(6)-a(3)=3d
    41-20=3d
    d=7

    from which
    a(3)=a(1)+(3-1)7
    a(1)=20-14=6

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