mathematics

Three times the reciprocal of the sum of two consecutive odd integers is 3/20. Find the two consecutive off integers.

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  1. Let 2n-1 be the smaller odd integer, then
    2n+1 is the larger.

    Given
    3/(2n-1 + 2n+1)=3/20
    3/(4n)=3/20
    4n=20
    n=5
    The integers are 2*5-1=9 and 2*5+1=11.

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