# algebra

rewrite as an equivalent loganthmic

e-^2=0.1353

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1. Given:
e^(-2)=0.1353
Take (natural) log on both sides:
log(e^(-2))=log(0.1353) ...(1)

Since log(base n)n^x = x
then logee^x = x

We rewrite the previous expression (1) as
-2 = loge(0.1353)
or
loge(0.1353) = -2

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