trig

prove as an identity
1/1+sin(x) + 1/1-sin(x)

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asked by mel
  1. oops i forgot the =2sec^2

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    posted by mel
  2. identities are equations.
    I don't see an equation.

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    posted by Reiny
  3. so it is 1/(1+sinx) + 1/(1-sinx) = 2sec^2 x

    LS
    = (1 - sinx + 1 + sinx)/((1+sinx)(1-sinx))
    = 2/(1 - sin^2x)
    = 2 cos^2x
    = 2sec^2x
    = RS

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    posted by Reiny

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