# trig

prove as an identity
1/1+sin(x) + 1/1-sin(x)

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asked by mel
1. oops i forgot the =2sec^2

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posted by mel
2. identities are equations.
I don't see an equation.

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posted by Reiny
3. so it is 1/(1+sinx) + 1/(1-sinx) = 2sec^2 x

LS
= (1 - sinx + 1 + sinx)/((1+sinx)(1-sinx))
= 2/(1 - sin^2x)
= 2 cos^2x
= 2sec^2x
= RS

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posted by Reiny

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